2x^2-8x+16=

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Solution for 2x^2-8x+16= equation:


Simplifying
2x2 + -8x + 16 = 0

Reorder the terms:
16 + -8x + 2x2 = 0

Solving
16 + -8x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(8 + -4x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(8 + -4x + x2)' equal to zero and attempt to solve: Simplifying 8 + -4x + x2 = 0 Solving 8 + -4x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-8' to each side of the equation. 8 + -4x + -8 + x2 = 0 + -8 Reorder the terms: 8 + -8 + -4x + x2 = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -4x + x2 = 0 + -8 -4x + x2 = 0 + -8 Combine like terms: 0 + -8 = -8 -4x + x2 = -8 The x term is -4x. Take half its coefficient (-2). Square it (4) and add it to both sides. Add '4' to each side of the equation. -4x + 4 + x2 = -8 + 4 Reorder the terms: 4 + -4x + x2 = -8 + 4 Combine like terms: -8 + 4 = -4 4 + -4x + x2 = -4 Factor a perfect square on the left side: (x + -2)(x + -2) = -4 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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